Slater's Rules


Determine the effective nuclear charge (Z*) for a valence electron in the following atoms or ions.
1. As+
2. S
3. Cr
4. Pd2+
5. Cu+
6. Br
7. Ge2−
8. F
9. Si
10. Fe
11. Co+
12. Ga
13. Cu
14. As5+
15. Sr
16. S2−
17. Fe2+

 

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Solutions


  
1. As+: (1s2)(2s2,2p6)(3s2,3p6)(3d10)(4s2,4p2)

S = (3 × 0.35) + (18 × 0.85) + (10 × 1.00) = 26.35

Z* = Z − S = 33 − 26.35 = 6.65
   
   
  
2. S: (1s2)(2s2,2p6)(3s2,3p4)

S = (5 × 0.35) + (8 × 0.85) + (2 × 1.00) = 10.55

Z* = Z − S = 16 − 10.55 = 5.45
   
   
  
3. Cr: (1s2)(2s2,2p6)(3s2,3p6)(3d5)(4s1)

S = (13 × 0.85) + (10 × 1.00) = 21.05

Z* = Z − S = 24 − 21.05 = 2.95
   
   
  
4. Pd2+: (1s2)(2s2,2p6)(3s2,3p6)(3d10)(4s2,4p6)(4d8)

S = (7 × 0.35) + (36 × 1.00) = 38.45

Z* = Z − S = 46 − 38.45 = 7.55
   
   
  
5. Cu+: (1s2)(2s2,2p6)(3s2,3p6)(3d10)

S = (9 × 0.35) + (18 × 1.00) = 21.15

Z* = Z − S = 29 − 21.15 = 7.85
   
   
  
6. Br: (1s2)(2s2,2p6)(3s2,3p6)(3d10)(4s2,4p6)

S = (7 × 0.35) + (18 × 0.85) + (10 × 1.00) = 27.75

Z* = Z − S = 35 − 27.75 = 7.25
   
   
  
7. Ge2−: (1s2)(2s2,2p6)(3s2,3p6)(3d10)(4s2,4p4)

S = (5 × 0.35) + (18 × 0.85) + (10 × 1.00) = 27.05

Z* = Z − S = 32 − 27.05 = 4.95
   
   
  
8. F: (1s2)(2s2,2p6)

S = (7 × 0.35) + (2 × 0.85) = 4.15

Z* = Z − S = 9 − 4.15 = 4.85
   
   
  
9. Si: (1s2)(2s2,2p6)(3s2,3p2)

S = (3 × 0.35) + (8 × 0.85) + (2 × 1.00) = 9.85

Z* = Z − S = 14 − 9.85 = 4.15
   
   
  
10. Fe: (1s2)(2s2,2p6)(3s2,3p6)(3d6)(4s2)

S = (1 × 0.35) + (14 × 0.85) + (10 × 1.00) = 22.25

Z* = Z − S = 26 − 22.25 = 3.75
   
   
  
11. Co+: (1s2)(2s2,2p6)(3s2,3p6)(3d8)

S = (7 × 0.35) + (18 × 1.00) = 20.45

Z* = Z − S = 27 − 20.45 = 6.55
   
   
  
12. Ga: (1s2)(2s2,2p6)(3s2,3p6)(3d10)(4s2,4p1)

S = (2 × 0.35) + (18 × 0.85) + (10 × 1.00) = 26.00

Z* = Z − S = 31 − 26.00 = 5.00
   
   
  
13. Cu: (1s2)(2s2,2p6)(3s2,3p6)(3d10)(4s1)

S = (18 × 0.85) + (10 × 1.00) = 25.30

Z* = Z − S = 29 − 25.30 = 3.70
   
   
  
14. As5+: (1s2)(2s2,2p6)(3s2,3p6)(3d10)

S = (9 × 0.35) + (18 × 1.00) = 21.15

Z* = Z − S = 33 − 21.15 = 11.85
   
   
  
15. Sr: (1s2)(2s2,2p6)(3s2,3p6)(3d10)(4s2,4p6)(5s2)

S = (1 × 0.35) + (8 × 0.85) + (28 × 1.00) = 35.15

Z* = Z − S = 38 − 35.15 = 2.85
   
   
  
16. S2−: (1s2)(2s2,2p6)(3s2,3p6)

S = (7 × 0.35) + (8 × 0.85) + (2 × 1.00) = 11.25

Z* = Z − S = 16 − 11.25 = 4.75
   
   
  
17. Fe2+: (1s2)(2s2,2p6)(3s2,3p6)(3d6)

S = (5 × 0.35) + (18 × 1.00) = 19.75

Z* = Z − S = 26 − 19.75 = 6.25
   
   
  

 

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